Hola.
6 X Y2/5 3 1/36*2/5 = x*3 = y*1/3, daqui vc tira:
1) 3x = 12/5, x = 4/5
2) x*3 = y*1/3
3*4/5 = y/3, y = 36/5
02) Determinar X Y Z nas sucessões inversamente proporcionais:16 6 y 10x 2/3 4/5 z
16/x = 6/(2/3) = y/ 4/5 = 10/z, daqui vc tira que:
1) 16/x = 6/(2/3)
16/x = 6*(3/2), 16/x = 9, x = 16/9
2) 6/(2/3) = y/ 4/5
9 = 5y/4, y = 36/5
3) y/ 4/5 = 10/z
(36/5)/(4/5) = 10/z, (36/5)*(5/4) = 10/z
9 = 10/z, z = 10/9