Log de raiz quadrada de 8 na base 4 => vamos chamar de "a"

Log de 1/3 na base 9 => vamos chamar de "b"

antilog -2 na base 2 => vamos chamar de "c"
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4^a = 8^(1/2)

[2^(2)]^a = [2^3]^(1/2)

2^(2a) = 2^(3/2)

2a = 3/2

a = 3/4

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9^b= 1/3

(3^2)^b = 3^(-1)

3^(2b) = 3^(-1)

2b = -1

b = -1/2

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c = 2^(-2)

c = 1/(2^2)

c = 1/4

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a + b + c = (3/4) + (-1/2) + (1/4)

a + b + c = 1/2